Question

please help. its very urgent.​

Answer 1

Answer:

$\mathcal {\textcolor{red}{(B)}}$

Step-by-step explanation:

We have:

$</p><p>a=b+ \frac{bx}{100}\\</p><p>b=a-\frac{ay}{100}\\</p><p>\implies x= \frac{100(a-b)}{b}\\</p><p>\text{And}\: y=\frac{100(a-b)}{a}\\</p><p>\text{Thus,}\\</p><p>\frac{1}{y}-\frac{1}{x}= \frac{a-b}{100(a-b)}\\</p><p>=\frac{1}{100}$