Question

please help karo meri.....saare steps k saath

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Answer 1

Step-by-step explanation:

It is of the form: (a+b)^3

(a+b)^3 = a^3 + b^3 + 3*a*b*(a+b)

Here, a = sin^2 theta, b = cos^2 theta

(sin^2 theta + cos^2 theta)^3 = sin^6 theta + cos^6 theta + 3*sin^2 theta * cos^2 theta * (sin^theta + cos^2 theta)

                =  sin^6 theta + cos^6 theta + 3*sin^2 theta * cos^2 theta

[sin^2 theta + cos^2 theta = 1]

Hence,

1 =  sin^6 theta + cos^6 theta + 3*sin^2 theta * cos^2 theta

Proved.

Answer 2

Answer:

at first multiply cos²∅ by 1 ( as multiply by 1 doesn't effect )

       then in the place of 1 put the formula of sin² + cos² = 1

  then u will get

 ( sin² + cos² )³ = 1

1³ = 1

hence proved