Question

PLEASE HELP .MATHS (LOGARITHM)

Answer 1

Step-by-step explanation:

let a^1/x=b^1/y=c^1/z=k

since, a^1/x=k

then a=k^x .......(1)

similarly b=k^y .......(2)

and c=k^z .......(3)

A.T.Q.

b^2=ac

(k^y)^2=k^x×k^z

k^2y=k^(x+z) {from equa 1,2 and 3}

since bases are equal then powers are also equal, therefore,

2y=x+z