Question

please help me..........​

Answer 1

Explanation:

Let charges are

$</p><p>q,Q−q$

<br>

$</p><p>F=kq(Q−q)=k(qQ− {q}^{2} )$

<br> for

$F$

to be maximum <br>

$</p><p> \frac{dF}{dq} =0⇒1Q−2q=0⇒q= \frac{Q}{2} </p><p>$

<br> Charges are

$</p><p> \frac{Q}{2}</p><p></p><p>,</p><p> \frac{Q}{2} </p><p>$

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Answer 2

Let charges are

q,Q−qq,Q−q

<br>

F=kq(Q−q)=k(qQ− {q}^{2} )F=kq(Q−q)=k(qQ−q

2

)

<br> for

FF

to be maximum <br>

\frac{dF}{dq} =0⇒1Q−2q=0⇒q= \frac{Q}{2}

dq

dF

=0⇒1Q−2q=0⇒q=

2

Q

<br> Charges are

\frac{Q}{2} , \frac{Q}{2}

2

Q

,

2

Q