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<7 = 180 - <6 (Liner Pair)
= 180 - (3y+20)
= 180 - (60+20)
= 180 - 80
= 100°
<8 = <6 ( Verticaly opposite angles)
= 60 +20
= 80°
= 180 - (3y+20)
= 180 - (60+20)
= 180 - 80
= 100°
<8 = <6 ( Verticaly opposite angles)
= 60 +20
= 80°
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TANU81:
Thx a lot ....
Answered by
7
HELLO DEAR,
line L || m and line "n" is TRANSVERSAL
<4= <6 [ alternate interior]
=> x+2y=3y+20
=> x-y = 20
=> x -y = 20 -----------(1)
<1+<4 =180° [straight line]
=> 2x+y+x+2y =180°
=> 3x+3y =180°
=> x+y =60°------------(1)
from--(1) and--(2)
we get,
x-y =20
x+y =60
--------------
2x =80
x=40° put in --(1)
we get,
40-y =20
y =40-20
=> y = 20°
<6 =(3×20+20) = (60°+20°) =80°
<7 + <6 =180° [ angles of straight lines]
=> <7 =180°-80°
=> <7 =100°
and <6 = <8 [vertically apposi.]
<8 =80°
I HOPE ITS HELP YOU DEAR,
THANKS
line L || m and line "n" is TRANSVERSAL
<4= <6 [ alternate interior]
=> x+2y=3y+20
=> x-y = 20
=> x -y = 20 -----------(1)
<1+<4 =180° [straight line]
=> 2x+y+x+2y =180°
=> 3x+3y =180°
=> x+y =60°------------(1)
from--(1) and--(2)
we get,
x-y =20
x+y =60
--------------
2x =80
x=40° put in --(1)
we get,
40-y =20
y =40-20
=> y = 20°
<6 =(3×20+20) = (60°+20°) =80°
<7 + <6 =180° [ angles of straight lines]
=> <7 =180°-80°
=> <7 =100°
and <6 = <8 [vertically apposi.]
<8 =80°
I HOPE ITS HELP YOU DEAR,
THANKS
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