Math, asked by Anonymous, 1 month ago

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Answered by vipinkumar212003
1

 \frac{x - 1}{x - 2}  +  \frac{x - 3}{x - 4}  = 3 \frac{1}{3}  \\  \frac{(x - 1)(x - 4) + (x - 3)(x - 2)}{(x - 2)(x - 4)}  =  \frac{10}{3}  \\  \frac{ {x}^{2}  - 4x - x  + 4 +  {x}^{2}  - 2x - 3x + 6}{ {x}^{2}  - 4x - 2x + 8}  =  \frac{10}{3}  \\  \frac{2 {x}^{2}  - 10x + 10}{ {x}^{2}  - 6x + 8}  =  \frac{10}{3}  \\ now \: cross \: multiply :  \\ 3(2 {x}^{2}  - 10x + 10) = 10({x}^{2}  - 6x + 8) \\ 6  {x}^{2}  - 30x + 30 = 10 {x}^{2}  - 60x + 80 \\ 0 = 10 {x}^{2}  - 6 {x}^{2}  - 60x + 30x + 80 - 30 \\ 0 = 4 {x}^{2} -  30x + 50 \\   0 = 4 {x}^{2}  - 20x - 10x + 50 \\ 0 = 4x (x - 5) - 10(x - 5) \\ 0 = (4x - 10)(x - 5) \\ x =  \frac{10}{4}   =  \frac{5}{2} \: , \: 5

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Answered by jagadhes1979
3

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