Question

PLEASE HELP ME ♥️♥️♥️♥️♥️

Answer 1

Hey mate

Here is ur answer
$1 \div (a + b + x) = 1 \div a + 1 \div b + 1 \div x \\ 1 \div (a + b + x) = (bx + ax + ab) \div abx \\ abx = abx + {a}^{2} x {a}^{2} b + {b}^{2} x + abx + a{b}^{2} + b {x}^{2} + a {x}^{2} + abx \\ a {x}^{2} + b {x}^{2} + a {x}^{2} + abx + abx + b {x}^{2} + {a}^{2} b + a {b}^{2} = 0 \\ {x}^{2} (a + b) \ + ax(a + b) + bx(a + b) + ab(a + b) = 0 \\ (a + b)( {x}^{2} + ax + bx + ab) = 0 \\ since \: a + b = 0 \\ so \: {x}^{2} + ax + bx + ab = 0 \\ x(x + a) + b(x + a) = 0 \\ (x + a)(x + b) = 0 \\ x = -a \: \: x = - b$

Answer 2

HEY!!..
.
.
☺️☺️☺️☺️
YOUR ANSWER IN THIS PHOTO......

❤️❤️ HOPE IT HELPS YOU❤️❤️