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Dear friend:-) :-) :-) :-) :-) :-) :-)
Let the smaller part be x.
∴ The larger part is (16 – x).
Given, 2 × (Larger part)2 = (Smaller part)2 + 164
∴ 2 (16 – x)2 = x2 + 164
⇒ 2 (256 – 32x + x2) = x2 + 164
⇒ 512 – 64x + 2x2 = x2 + 164
⇒ x2 – 64x + 348 = 0
⇒ x2 – 58x – 6x + 348 = 0
⇒ x (x – 58) –6 (x – 58) = 0
⇒ (x – 58) (x –6) = 0
⇒ x – 58 = 0 or x – 6 = 0
⇒ x = 58 or x = 6
⇒ x = 6 (�x cannot be 58)
∴ Smaller part = x = 6
Larger part = 16 – x =16 – 6 = 10
Cheers!
Let the smaller part be x.
∴ The larger part is (16 – x).
Given, 2 × (Larger part)2 = (Smaller part)2 + 164
∴ 2 (16 – x)2 = x2 + 164
⇒ 2 (256 – 32x + x2) = x2 + 164
⇒ 512 – 64x + 2x2 = x2 + 164
⇒ x2 – 64x + 348 = 0
⇒ x2 – 58x – 6x + 348 = 0
⇒ x (x – 58) –6 (x – 58) = 0
⇒ (x – 58) (x –6) = 0
⇒ x – 58 = 0 or x – 6 = 0
⇒ x = 58 or x = 6
⇒ x = 6 (�x cannot be 58)
∴ Smaller part = x = 6
Larger part = 16 – x =16 – 6 = 10
Cheers!
jaskaransandhep7oysc:
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yes up one is Right okkkkkkkkkk
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