Question

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Answer 1

hope it will help you

Answer 2

let usual speed be x

distance = speed × time

300= x × t

Now

300= (x+5)× ( t-2)

300 = xt - 2x + 5 t-10

300 = 300 - 2x + 5 t-10

2x - 5 t = -10

xt = 300

t= 300/x

put above

2x - 1500/x= -10

2 x.x - 1500 +10 x= 0

x.x - 750 + 5x = 0

x.x -25x +30 x -750= 0

x( x-25) +30( x-25)= 0

x= -30,25
neglect -30

So x= 25 km/h