Question

Please help me.....

Answer 1

Mate here's your answer

x-2/x-3+x-4/x-5=10/3

=› (x-2)(x-5)+(x-4)(x-3)/(x-3)(x-5)=10/3

=› (x^2-7x+10)+x^2-7x+12)/x^2-

8x+15=10/3

=› 2x^2-14x+22/x^2-8x+15=10/3

=› 3(2x^2-14x+22)=10(x^2-8x+15)

=› 6x^2-42x+66=10x^2-80x+150

=› 6x^2-10x^2-42x+80x+66-150=0

=› -4x^2+38x-84=0

=› -(4x^2-38x+84)=0

=› 4x^2-38x+84=0

=› 2(2x^2-19x+42)=0

=› 2x^2-19x+42=0

=› 2x^2-(7+12)x+42=0

=› 2x^2-7x-12x+42=0

=› x(2x-7)-6(2x-7)=0

=› (2x-7)(x-6)=0

Either,

2x-7=0 or x-6=0

=› 2x=7 =› x=6

=› x=7/2

Hope it helps☺