Question

please help me......​

Answer 1

hope this will help you.

Answer 2

$\frac{ {a}^{ - 1} }{ {a}^{ - 1} + {b}^{ - 1} } + \frac{ {a}^{ - 1} }{ {a}^{ - 1} - {b}^{ - 1} } = \frac{2 {b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{ \frac{1}{a} }{ \frac{1}{a} + \frac{1}{b} } + \frac{ \frac{1}{a} }{ \frac{1}{a} - \frac{1}{b} } = \frac{2 {b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{ \frac{1}{a} }{ \frac{b + a}{ab} } + \frac{ \frac{1}{a} }{ \frac{b - a}{ab} } = \frac{2 {b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{ab}{a(b + a)} + \frac{ab}{a(b - a)} = \frac{2 {b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{b}{b + a} + \frac{b}{b - a} = \frac{2 {b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{b(b - a) + b(b + a)}{(b + a)(b - a)} = \frac{2 {b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{ {b}^{2} - ab + {b}^{2} + ab}{ {b}^{2} - {a}^{2} } = \frac{ 2{b}^{2} }{ {b}^{2} - {a}^{2} } \\ \\ \frac{ {2b}^{2} }{ {b}^{2} - {a}^{2} } = \frac{ {2b}^{2} }{ {b}^{2} - {a}^{2} }$