Question

please help me........ ​

Answer 1

$\sqrt{16 - 6 \sqrt{7} } \\ = \sqrt{16 - 2 \sqrt{9 \times 7} } \\ = \sqrt{7 + 9 - 2 \sqrt{9} \sqrt{7} }$

This is in form

${x}^{2} - 2xy + {y}^{2} = {(x - y)}^{2}$

Hence

$= \sqrt{( {3 - \sqrt{7}) }^{2} } \\ = 3 - \sqrt{7}$

Here a=3

b=-1

Answer 2

Answer:

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