Question

PLEASE HELP ME... a wire of resistance 6 Ohm is streached to twice of its original length.what will be it's. new resistance? #NO SPAM ​

Answer 1

Answer:

Explanation:

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Original length of wire= l1

New length of wire =2l1

Reistance of wire =R1=6 ohms

Resistance of new wire=?

we know that :

R1=ρ l1/A1-----------------1

When length is doubled  

Volume of wire remains same :

A1x 11= A2x l2

l2=2l1

so

A1xl1=A2x2lx1

A2=A1/2 -------------2

R2=ρ l2/A2

R2=ρ[2l1/A1/2]

R2=4[ρl1/A1] [ from equation 1]

R2= 4xR1

=4x6=24 ohms

Answer 2

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