Question

please help me and explain too​

Answer 1

Hey mate!!

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as, pd/Baso4 is reducing agent

so, product formed at A will be

ethane. CH4-CH4

now, when it is treated with alc. KMnO4

which is a oxidising agent

product formed at B will be,

ethane 1,2 diol

CH2OH - CH2OH (or ethylene glycol)

hope it helps!!

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