Question

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Answer 1

Answer:

hope it will help you......

Answer 2

This question comes under the topic differentiation of parametric functions

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} } \: \: \: \: \: \: \: - (1)$

So,

$y = 2at$

$\frac{dy}{dt} = 2a$

Also,

$x = at {}^{2}$

$\frac{dx}{dt} = 2at$

Putting in eq 1

$\frac{dy}{dx} = \frac{2a}{2at}$

$\frac{dy}{dx} = \frac{1}{t}$

Putting value of t from y = 2at

t = y/2a

dy/dx = 2a/y

Note : You can also put value of t from x = at²