Question

please help me and wrong answer will be reported so please give the right answer​

Answer 1

Hope this helps you ;)

$(k - 2)x + 4y = 10$

$given \: x = 2 \: and \: y = 1$

On substituting x and y,

$(k - 2) \times 2 + 4(1) = 10$

$(k - 2) \times 2 = 10 - 4$

$(k - 2) = \frac{6}{2}$

$k = 3+ 2$

$k = 5$

Answer 2

Answer:

Hope this helps you ;)

(k - 2)x + 4y = 10(k−2)x+4y=10

given \: x = 2 \: and \: y = 1givenx=2andy=1

On substituting x and y,

(k - 2) \times 2 + 4(1) = 10(k−2)×2+4(1)=10

(k - 2) \times 2 = 10 - 4(k−2)×2=10−4

(k - 2) = \frac{6}{2}(k−2)=

2

6

k = 3+ 2k=3+2

k = 5k=5