Math, asked by Salomi2004, 7 months ago

please help me.............answer in detail ​

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Answered by samuelWilson
1

I myself am weak in maths and want third, fifth and second question.......

Answered by gr8glory08
0

hey friend ,

here is ur answer

1)  3x ² + ( k- 3 )x + 9 = 0

  3 ( 3) ² + ( k-3) 3 + 9 = 0    [ put x = 3 ]

  3 x 9 + 3k - 9 + 9 = 0   [ multiply 3 by ( k-3 ) u get 3k - 9 ]

  27 + 3k = 0   {as we know (-) x ( +) = ( - ) so [-9] and [+9] will be 0 }

  3k = -27  [ get 27 to the place of 0 it will become -27 ]

  k = - 27 / 3  [ divide 3 with -27]

 k = -9

u can cross check the answer if there are any mistakes

2) There is a difference of one in consecutive positive integers

let 1 st integer = x

second be = (x + 1 )

give that sum of squares is 365

∴ ( 1st integer )² + ( 2nd integer )² = 365

∴ ( x )² + ( x + 1)² = 365

∴ x ² + x² + 1² + 2 × x + 1  = 365

∴ 2x² + 1 + 2x = 365

∴ 2x² + 2x + 1 - 365 = 0

∴ 2x² + 2x - 364 = 0

∴ 2 ( x² + x - 182 ) = 0

∴ x² + x - 182 = 0 / 2

∴ x² + x - 182 = 0

we factorize by splitting the middle term method

x² + 14x - 13x - 182 = 0

x( x+ 14 ) - 13 ( x+ 14 ) = 0

( x + 14 ) ( x - 13) = 0

x + 14 = 0                            x - 13 = 0

x = - 14                                x = 13

so the root of the give equation are x = -14 and x = 13

since we have to find positive integers we take x = 13

1st number = 13

2nd number = 1 + x

                    = 1 + 13

                    = 14

5)  Let the speed of train be x km/ hr

   NORMAL SPEED

  Distance = 360 km

  Speed = x km/hr

  Speed =  distance / time

  ∴ x = 360 / time

  ∴ time = 360 / x

  Speed 5 km/ hr more

distance = 360 km

speed = ( x + 5 ) km /hr

time = ( 360 / x ) - 1

now ,

speed = distance / time

( x + 5) = 360 / ( 360 / x ) - 1

( x+ 5 ) ( 360 / x - 1) = 480 ..........( 1)

from (1)

( x+ 5) ( 360 / x-1 ) = 360

(  x+ 5) ( 360 - x / x ) = 360

( x + 5 ) ( 360 - x ) = 360 x

x  ( 360 - x ) + 5 ( 360 - x ) = 360 x

360 x - x² + 5 ( 360 ) - 5 x = 360 x

360 - x² + 1800 - 5 x = 360 x

360 x - x² + 1800 - 5x - 360x = 0

- x² - 5x  - 360x + 360x + 1800x = 0

- x² - 5x + 1800 = 0

∴ 0 = x² + 5x - 1800

∴ x² + 5x - 1800 = 0

we factorize by splitting the middle term method

x² + 45x  - 40x - 1800 = 0

x ( x+ 45 ) - 40 ( x + 45) = 0

( x + 45 ) ( x - 40 ) = 0

x + 45 = 0                       x - 40 = 0

x = -45                             x = 40

hence roots are x = -45 and x = 40

we know that the speed of the train cannot be negative  

hence,

x ≠ - 45

∴ the speed of the train is 40 km / hr

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