please help me answer it quickly
if the Inner radius of hemisphere bowl is 14cm. andits thickness is 7mm .find the cost of painting it at rate of 2 paise per square cm.
Answers
Solution:
◕ Inner diameter of the bowl (diameter)=14cm
◕ Inner radius of the bowl (radius) = 14/7 = 7cm
◕Metallic thickness ofvthe bowl =7mm =0.7cm
◕outer radius of the bowl =R = 7+.07
✿Area to be painted = inner surface area of hemisphere +outer surface area of hemisphere+ area ofvthe cross section ring of hemisphere
☞2πr²+2πR²+(πR²-πr²)
→2πr²+2πR²+πR²-πr²
→2πr²-πr²+2πR²+πR²
→3πR²+πr²
→3×22/7×7.7×7.7×22/7×7×7
→66×1.1×7.7×154
→559.02+154
→713.02 cm²
________________________________
Cost of painting = 2×713.02
☞ 1426.04 paise
☞Rs.14.26
Given : Inner radius of hemisphere bowl is 14cm. and its thickness is 7mm. cost of painting it at rate of 2 paise per square cm
To find : Total Cost of Painting
Solution:
Inner radius = 14 cm
Thickness = 7mm = 0.7 cm
Outer radius = 14 + 0.7 = 14.7 cm
Area to be painted
= 2π(14.7)² + 2π(14)² + ( π(14.7)² - π(14)² )
= 3π(14.7)² + π(14)²
using π = 22/7
=> 3(22/7) (14.7)² + (22/7) (14)²
= 66 * 14.7 * 2.1 + 22 * 14 * 2
= 2037.42 + 616
= 2653.42 cm²
cost of painting at rate of 2 paise per square cm = 2653.42 * 2 / 100 Rs
= 53.0684 Rs
cost of painting = 53.0684 Rs
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