Question

Please help me answer this

Answer 1

1÷(sec x - tan x) - 1÷cos x = 1÷ cos x - 1÷ (sec x + tan x)

1÷ ( sec x-tan x) + 1÷ (sec x + tan x) = 1÷ cos x+ 1 ÷ cos x

[(sec x + tan x)+ (sec x- tan x)]÷

(sec x + tan x)×(sec x - tan x) = 2 / cos x

2 sec x ÷ ( sec square x - tan square x) = 2 / cosx

hence, by the trignometric identities

sec square x - tan square x = 1

so,

2 sec x ÷ 1 = 2 / cos x

we know , sec x = 1 / cos x

so,

2 / cos x = 2 / cos x

" HENCE PROVED "

IT HELPS YOU!!!

MARK ME AS BRAINLIST!!!