Question

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Answer 1

Answer:

1.   PQ = 5

2.   5:5   AND   5:5

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Answer 2

Answer:

PQ = 5

CP/PA = 1

CQ/QB = 1

Step-by-step explanation:

In ΔABC

Seg PQ || sideAB

.:By midpoint theorem, the line segment in a triangle joining the midpoint of two sides of thetriangle is said to be parallel to its third side and is also half of the length of the third side.

$PQ = \frac{1}{2}AB = \frac{1}{2} \times 10 = 5$

P is midpoint of the side CA

.: CP = PA

$\frac{CP}{PA} = \frac{1}{1} = 1$

Q is midpoint of the side CB

.: CQ = QB .

$\frac{CQ}{QB} = \frac{1}{1} = 1$