please help me.
answer this question
A 376g of zinc at 66°C is placed in a 345g Aluminium calorimeter that contains 610g of water at 19°C. What is the final temperature of the mixture?
C(Aluminium) =900J/Kg K
C(Zinc) =387 J/kg K
C(water)=4186 J/Kg K
Answers
Explanation:
please follow me if you like my solution so that I may solve ur further problems as soon as possible
Answer:
The final temperature of the mixture is 21.3°C.
Explanation:
From the above Question,
The capability of zinc:
Q_1_1.1 = m_1 × c_1 × ΔT1
where,
m_1 = 376g
c_1 = 387 J/kg K
ΔT1 = T1 - T0
= (66 - 19)°C
ΔT1 = 47°C
Q_1_11 = 376g × 387 J/kg K × 47°C
Q_1_11 = 7,303,668 J
Q_1_12 = m2 × c2 × ΔT2
where,
m2 = 345g + 610g
= 955g
c2 = 900 J/kg K
ΔT2 = T0 - 19°C
= 19°C
Q_1_12 = 955g × 900 J/kg K × 19°C
Q_1_12 = 16,347,000 J
The sum of Q_1_11 and Q_1_12:
Q_1_1 = Q_1_11 + Q_1_12
Q_1_1 = 7,303,668 J + 16,347,000 J
Q_1_1 = 23,650,668 J
Q_1_1 = m3 × c3 × ΔT3
Simplifying:
c3 = 17.74 J/g K
To find Tf:
Tf = Q_1_1 / (m3 × c3) + T0
Tf = 23,650,668 J / (1331g × 17.74 J/g K) + 19°C
Tf = 21.3°C
Therefore,
The final temperature of the mixture is 21.3°C.
For more such related questions : https://brainly.in/question/52199656
#SPJ2