Question

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Answer 1

Relative density of pure gold = 19.3

Weight of the gold bangle as per the jeweller

= 41.495 g

We know that ,

whenever an object is placed in water upthrust acting on the object is equal to to its weight

and the volume of the water displaced= volume of the object

hence we can conclude that,

volume of gold bangle = volume of water displaced

weight of the bangle in water= 39.345 g

difference in weight of the bangle

= weight of the bangle in air - weight of the bangle in water

= 41.495-39.345

= 2.15 g

mass of the water displaced = 2.15 g

density of water displaced = 1 g / cm³

we know that ,

$\displaystyle \star \mathtt{ \green{density = \frac{mass}{volume} }}$

$\implies \mathtt{volume = 2.15 \: {cm}^{3} }$

volume of water displaced = volume of a gold bangle= 2.15 cm³

Relative density of pure gold = 19.3 g / cm³

volume of a gold bangle= 2.15 cm³

$\implies \mathtt{mass = 19.3 \times 2.15}$

$\implies{ \mathtt{ \red{mass = 41.495g}}}$

hence we can conclude that the bangle is made up of pure gold

Answer 2

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The relative density of pure gold is known to be 19.3 . A customer buys a, weighing 41.495 g from a jeweller. To check that the bangle is made of pure gold, the customer weight the the bangle in water where it is found to weigh 39.345 g. Do appropriate calculation and help the coustomer to decide as to whether the bangle, he bought, is made of pure gold or not ?

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Relative density of pure gold = 19.3

Weight of the gold bangle as per the jeweller

= 41.495 g

We know that ,

whenever an object is placed in water upthrust acting on the object is equal to to its weight

and the volume of the water displaced= volume of the object

hence we can conclude that,

volume of gold bangle = volume of water displaced

weight of the bangle in water= 39.345 g

difference in weight of the bangle

= weight of the bangle in air - weight of the bangle in water

= 41.495-39.345

= 2.15 g

mass of the water displaced = 2.15 g

density of water displaced = 1 g / cm³

we know that ,

$\displaystyle \star \mathtt{ \blue{density = \frac{mass}{volume} }}⋆density \: = </p><p>volume \: mass \\ \implies \mathtt{volume = 2.15 \: {cm}^{3} } \\ ⟹volume=2.15cm ³$

volume of water displaced = volume of a gold bangle= 2.15 cm³

Relative density of pure gold = 19.3 g / cm³

volume of a gold bangle= 2.15 cm³

$\implies \mathtt{mass = 19.3 \times 2.15} \\ ⟹mass=19.3×2.15 \\ \implies{ \mathtt{ \blue{mass = 41.495g}}} \\ ⟹mass=41.495g$

hence we can conclude that the bangle is made up of pure gold