Question

please help me (ap arithmetic progression )​

Answer 1

Answer:

Rs. 52,350

Step-by-step explanation:

According to question,

t1=a=6000

d=-250

Extra Price (e) = 3150

t12=b=?

S12=?

We know,

t12 = a + 11d = 6000 + 11* -250 = 6000 - 2750 = 3250

S12 = (n/2)(a+b) = (12/2)(6000+3250) = 6*9250 = 55500

Original Price of scooter = S12 - e = 55500 - 3150 = 52,350

∴The original price of the scooter is Rs. 52,350

I hope it is the right answer.