please help me as fast as u can..
answer will be marked as brainlist
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[cosx cosecx-sinx secx]/[cosx+sinx]
[(cosx/sinx)-(sinx/cosx)]/[cosx+sinx][(cos^2x-sin^2x)/sinxcosx]/[cosx+sinx]
=[(cosx-sinx)(cosx+sinx)]/[(cosx+sinx)
(sinxcosx)
=[(cosx-sinx)/sinxcosx]
=(cosx/sinxcosx)-(sinx/sinxcosx)
=(1/sinx)-(1/cosx)
=cosecx-secx
Yazlin:
tnx for the brainliest
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