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Q. Two supplementary angles are in the ratio 4:5. Find the measures of the angles.
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6
Let the angles be x
As they are in ratio of 4:5 ,so we can write it in the form of 4x ,5x
We know supplementary angle =180°
so,According to the question
4x+5x =180°
9x =180°
x =180°÷9
x =20°
so , 1 st angle = 4x =4×20° =80°
2 nd angle = 5x = 5×20° =100°
◆PROOF◆
4x + 5x =180°
4×20° +5×20° =180°
80°+ 100°=180°
180° =180°
[VERIFIED]
As they are in ratio of 4:5 ,so we can write it in the form of 4x ,5x
We know supplementary angle =180°
so,According to the question
4x+5x =180°
9x =180°
x =180°÷9
x =20°
so , 1 st angle = 4x =4×20° =80°
2 nd angle = 5x = 5×20° =100°
◆PROOF◆
4x + 5x =180°
4×20° +5×20° =180°
80°+ 100°=180°
180° =180°
[VERIFIED]
nsopagu:
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Answered by
3
Let (180 - x) = smaller angle
Let x = bigger angle
Then 4x + 5x = 180
9x = 900
x = 900/9
x = 100
The bigger angle is 100.
Smaller angle = 180 - 100 or 80.
Let x = bigger angle
Then 4x + 5x = 180
9x = 900
x = 900/9
x = 100
The bigger angle is 100.
Smaller angle = 180 - 100 or 80.
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