Question

please help me by answering this question ​

Answer 1

Step-by-step explanation:

Sec(A) + tan(A) = p

= 1/cos(A) + Sin(A)/cos(A) = p

taking LCM of LHS:-

=(1+sin(A))/cos(A) = p

squaring both sides

=(1+sin(A))²/cos²(A) = p²

Now componendo and dividendo

=(1+sin(A))² + 1-sin²(A)/(1+sin²(A)-1+sin²(A)) =p²+1/p²-1

after taking common

1/sin(A) = p²+1/p²-1

now flipping upside down

sin(A) = p²-1/p²+1..... Hence proved