Question

please help me by answering this solution

Answer 1

Hey Mate here the answer..


If a dice thrown twice then,

The total outcomes will be (6)² = 36

1. Probability of not getting 4

Favourable outcomes = 36 - 11 = 25

P(e) = favorable outcomes/total outcomes

= 25/36 or 0.694



2. 7 will come atleast once.

Favorable outcomes = 11

P(e) = Favorable outcomes/total outcomes

= 11/36 or 0.305


Hope it will help you...