Question

please help me by solving this question​

Answer 1

Answer:

(i) <x = 100° [ corresponding angles ]

(ii) 5x = 3x +12° [ corresponding angles ]

5x -3x = 12°

2x = 12°

x = 12/2

x = 6°

5x = 5 ×6° = 30°

3x +12 = 3×6°+12° = 18°+12°= 30°

(iii) x+2x = 180° [ Co-interior angles ]

3x = 180°

x = 180/3

x = 60°

2x = 2×60° =120°

(iv) a = 2x-25

c = 3x +5

b =c. [ corresponding angles }

a + b = 180° [ linear pair ]

2x -25+3x+5 = 180°

5x -20 = 180°

5x = 180°+20°

5x = 200°

x = 200/5

x = 40°

2x -25 = 2×40°-25° = 80°-25°= 55°

3x +5 = 3×40°+5 = 120°+5°= 125°

(v) <x = 130° [ alternate interior angle ]

<x = <y [ corresponding angles ]

<y = 130°

<y + <Z = 180° [ co-interior angles ]

130° + <Z = 180°

<Z = 180°-130°

<Z = 50°