Question

please help me ✔️✔️✔️✔️✔️✔️✔️✔️✔️
class 10 maths

Answer 1

SOLUTION

$if \: a \: be \: the \: first \: term \: of \: an \: AP \\ and \: d \: be \: its \: common \: difference \:of \: AP \\ \\ than \: nth \: term \: can \: be \: written \: as \\ t(nth) = a + (n - 1)d \\ \\ so \: 24th \: term \: = a + 23d....(1) \\ 10th \: term = a + 9d......(2) \\ \\ acc \: to \: question \\ 24th \: term = 2 \times (10th \: term) \\ a + 23d = 2 \times (a + 9d) \\ a + 23d = 2a + 18d \\ a = 5d......(3) \\ \\ 72nd \: term = a + 71d \\ put \: (3) \: here \\ 72nd \: term = 76d \\ \\ 34th \: term = a + 33d \\ 34th \: term = 5d + 33d \\ 34th \: term = 38d \\ multiply \: by \: 2 \\ 2(34th \: term) = 76d \\ \\ 2 \times 34th \: term = 72nd \: term$

Answer 2

Hey !! kaha ho aap ............ yeh new account hai mera wo wala delete hongya hai..... please ana ek baar mere que pe.

waise kuch jada busy nhi jo aap.