Question

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Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Given that,

Tan^-1(2x)+tan^-1(3x)=π/4

Now apply the formula as follows

Tan^-1(a)+tan ^-1(b)=tan^-1(a+b/1-ab)

Now,

Tan^-1(5x/1-6x²)=tan^-1(π/4)

This function is cancelled.....

5x/1-6x²=1

1-6x²=5x

6x²+5x-1=0

6x²+6x-5x-1=0

6x(x+1)-5(x+1)=0

6x=5, x=-1

X=5/6,-1

Step-by-step explanation:

Hope it helps you frnd..........