Math, asked by friendsforever7244, 6 months ago

please HelP me DeaR FrieNds
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so if anYone Give Me irrelevant answer sO I will directly report It


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Answers

Answered by d14sr
1

Answer:

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1st ans:- 10 cm

2nd ans:- 4.17 cm

3rd ans:- 12 cm²

4th ans:- 24cm

Step-by-step explanation:

-> First Explanation:-

Pythagoras theorem, we know that

AC^2 = AB^2 + BC^2

          = (12)^2 + (16)^2

          = 144 + 256

          = 400.

AC = 20

Diameter of the circle = 20cm.

Radius will be r = d/2

                      = 10 cm

-> Second Explanation:-

Given : - CD is diameter which meets chord AB in E

AE = BE = 4 cm , CE = 3 cm.

To find : - Radius of the circle.

Let the radius be R.

Then,

Mark a point O a the mid point of the circle and join OB. OB = OC = R .

So , OE = ( R - 3)

By pythagoras theorem,

(R - 3)² + (4)² = (R)²

=> R² - 6R + 9 + 16 = R²

=> R² - R² - 6R = - 25

=> 6R = 25

=> R = 25/6

=> R = 4.16 cm

->3rd Explanation:-

Length of on side of rectangle is 4cm.

Now diameter of circle is equal to diagonal of rectangle.

by Pythagoras theorem

the other side is 3 cm.

the area of rectangle is product of length and breadth

3×4=12

Hence, area of rectangle is 12cm²

-> 4th Explanation:-

The shortest chord must be perpendicular to AB line

Line AB also bisects the chord.

x × x = 18 × 8

x² = 144 cm

x = 12 cm

The length of shortest chord:

= 2 × 12

= 24 cm

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