Question

Please help me
develop
(√6 + 3) ²
(2x-√3) ²
(5x-√11) (5x + √11)
factoriz
x²-9
x²+2x√5+5
9x²-6x+1
x³-3
(3x-5)²-(x+2)²

Answer 1

Answer:

Solution

We have,

x

2

+6x−10=0

We know that

x=

2a

−b±

b

2

−4ac

Therefore,

x=

2×1

−6±

6

2

−4×1×−10

x=

2

−6±

36+40

x=

2

−6±

76

x=

2

−6±

19×4

x=

2

−6±2

19

x=−3±

19

Hence, this is the answer.