Please help me do my math home work i am stuck you can see the questions in the given below attachment.
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Step-by-step explanation:
1)Given that ∆PsQ=∆STU under ASA property then
=>Corresponding sides are equal
Corresponding angles are equal
=>Angle Q= angle T
angle R=angle U
=>angle U=30°
x=30°
and the sum of all angles in a triangle =180°
=>LP+LQ+LR=180°
=>LP+60°+30°=180°
=>LP+90°=180°
=>LP=180°-90°
=>LP=90°
LP=LS
=>Y=90°
2)In two triangles ,∆PSQ and ∆PSR
PQ=PR=6.5cm
LPSQ=LPSR=90°
PS=PS(common side)
By RHS property,
∆PSQ is congruent to ∆PSR
and QS=QR
(congruent parts are equal in Congruent triangles)
=>∆PSQ=∆PSR
3)From the two triangles ∆LMN and ∆ONM
LM=ON(given)
LN=OM(given)
MN=MN(common side)
By SSS Property,
∆LMN is congruent to ∆ONM
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