Question

Please help me do this​

Answer 1

Step-by-step explanation:

Taking the L.H.S, we have

3[4 x]+2[y −3]=[12 3x]+[2y −6]=[(12+2y) (3x−6)]

Now, equating with R.H.S we get

[(12+2y) (3x−6)]=[10 0]

12+2y=10 and 3x−6=0

2y=−2 and 3x=6

y=−1 and x=2