Question

Please help me doing this question

Answer 1

ACD=CAB=70--ALTERNATE ANGLES

ECD=180-CEF=180-130=50-------CO INTERIOR ANGLES

ACE=70-50=20(ANS)

Answer 2

Answer:

given: ab ll cd, cd ll ef

abllcd

<bac=<acd (alt. interior angles)

=> <acd=70

cdllef

<fec+<dce=180

(angles on the same side of transversal)

=> <dce=50

<ace= <acd - <dce

<ace= 70-50

<ace= 20

hope it helps u.....^_^