please help me doing this question..
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(x1/(a-b))1/(a-c) ×( x1/(b-c))1/(b-a) ×(x1/(c -a))1/(c -b)
= x ^1/(a - b)(a - c) × x 1/(b - c)(b - a) × x 1/(c - a)(c -b)
= x ^1/(a - b)(a - c) + 1/(b - c)(b - a) + 1/(c - a)(c -b)
= x ^1/(a - b)(a - c) - 1/(b - c)(a - b) - 1/(c - a)(b -c)
= x ^1/(a - b)(a - c) - 1/(b - c)(a - b) + 1/(a - c)(b -c)
= x ^(b -c) - (a - c) + (a - b)/(a - b)(b -c)(a - c)
= x ^(b -c - a + c + a - b)/(a - b)(b -c)(a - c)
= x^0/(a - b)(b -c)(a - c)
= x^0
= 1
= x ^1/(a - b)(a - c) × x 1/(b - c)(b - a) × x 1/(c - a)(c -b)
= x ^1/(a - b)(a - c) + 1/(b - c)(b - a) + 1/(c - a)(c -b)
= x ^1/(a - b)(a - c) - 1/(b - c)(a - b) - 1/(c - a)(b -c)
= x ^1/(a - b)(a - c) - 1/(b - c)(a - b) + 1/(a - c)(b -c)
= x ^(b -c) - (a - c) + (a - b)/(a - b)(b -c)(a - c)
= x ^(b -c - a + c + a - b)/(a - b)(b -c)(a - c)
= x^0/(a - b)(b -c)(a - c)
= x^0
= 1
Fishy:
di aapne bohot achche se explain kiya
thnkss
Hey
Hey fishy,,,,ur name is amaira bhardwaj
no...
and don't comment
Yaaa
I know u
Hello fishy
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