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Yes, ABCD is a parallelogram.
Solved proof is as follows:
Explanation:
Given:
A figure in which:
- l || m
- p || q
- p intersects l at A and m at B
- q intersects l at D and m at C
To prove: Δ ABC ≅ ΔCDA &
To find: Whether ABCD is a parallelogram
Proof:
In Δ ABC and ΔCDA,
- ∠BAC =∠DCA
( Alternate interior angles when p || q and AC is the transversal)
- AC = CA (Common)
- ∠BCA = ∠DAC
( Alternate interior angles when || m and AC is the transversal )
∴ By ASA congruency criteria, Δ ABC ≅ ΔCDA
⇒ AD = BC & AB = DC ( By C.P.C.T )
Now,
As opposite sides of quadrilateral ABCD are equal,
hence, ABCD is a parallelogram.
Hence, proved.
Hope you got that.
Thank You.
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