Question

please help me. factorisation ​

Answer 1

Answer:

this one will help you to do the refered question

Answer 2

Step-by-step explanation:

Given :-

[(0.87×0.87×0.87)+(0.13×0.13×0.13)]/[0.87×0.87-0.87×0.13+0.13×0.13]

To find :-

Simplify the given expression ?

Solution :-

Given expression is

[(0.87×0.87×0.87)+(0.13×0.13×0.13)]/[0.87×0.87-0.87×0.13+0.13×0.13]

=> [(0.87)^3+(0.13)^3]/[(0.87)^2-(0.87×0.87)+(0.13)^2]

Numerator is in the form of a^3+b^3

Where a = 0.87 and b = 0.13

We know that

a^3+b^3 = (a+b)(a^2-ab+b^2)

=> 0.87^3+0.13^3

=> (0.87+0.13)[(0.87)^2-(0.87×0.13)+(0.13)^2]

Now

it becomes

(0.87+0.13)[(0.87)^2-(0.87×0.13)+(0.13)^2] \[(0.87)^2-(0.87×0.87)+(0.13)^2]

=> (0.87+0.13)

=> 1.00

=> 1

Answer:-

The value of [(0.87×0.87×0.87)+(0.13×0.13×0.13)]/[0.87×0.87-0.87×0.13+0.13×0.13] is 1

Used formulae:-

• a^3+b^3 = (a+b)(a^2-ab+b^2)

More formulae to know :-

• (a+b)^2 = a^2+2ab+b^2

• (a-b)^2 = a^2-2ab+b^2

• (a+b)(a-b)=a^2-b^2

• (a+b)^3 = a^3+b^3+3ab(a+b)

• (a-b)^3=a^3-b^3-3ab(a-b)

• a^3-b^3 = (a-b)(a^2+ab+b^2)

• a^3+b^3 = (a+b)(a^2-ab+b^2)