Question

please help me fast...................​

Answer 1

Answer:

we know that AB||CD and t is a transversal cutting at E and F

From the figure we know that ∆BEF and ∆DFC are interior angle

SO, we get

∆BEF+∆DFE=189°

Dividing the entire equation by 2 we get

1/2 ∆BEF + 1/2 ∆DEF =90°

According to figure the above question can further be written as

∆GEF + ∆GFE = 90° .........(¡)

Answer 2

I have solved this Question, nymph of heaven girl...