Math, asked by sajujency, 1 year ago

Please help me . Fast
25 th problem

Attachments:

Answers

Answered by jvinayakg1014
1

a(1 - a) + 2(a - 3) + 5(3 - 1) = 0 \\  = a -  {a}^{2}  + 2a - 6 + 10 = 0 \\  =  -  {a}^{2}  + 3a + 4 = 0 \\  =  {a}^{2}  - 3a - 4 = 0 \\  =  {a}^{2}  - 4a + a - 4 = 0 \\  = a(a - 4) + 1(a - 4) \\ (a + 1)(a - 4) \\ a =  - 1 \\ a = 4


sajujency: Haven't understood .
sajujency: Plz explain it
jvinayakg1014: used the formula of area of triangle
Similar questions