Question

please help me fast in algebra​

Answer 1

YOUR QUESTION: Write the roots of the equation (x+3)(x-2)=0.

MY ANSWER:

$x^{3} -3x-2 =0$

Clearly x=−1 is a solution of the equation, hence (x+1) is a factor of the equation

$x^{2} -x-2$

Then divide $x^{3} - 3x -2$ by (x+1)

                         $\sqrt[x+1]{x^{3}-3x-2 }$

                             $x^{3} + x^{2}$

                        $\sqrt{-3x-2-x^{2}}$

                          $-x -x^{2}$

                     $\sqrt{-2x-2x}\\ -2x-2$

                       

⇒$x^{2} -x-2$

⇒$x^{2} +2x-x-2=0$

⇒$x(x+2)-1(x+2)=0$

⇒(x−1)(x+2)=0

$\boxed {Factors=>(x+1)(x-1)(x+2)=0}\\\boxed {Roots =>-1,1,-2.}$

$\mathbb{THANK\:YOU}$

Answer 2

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