Math, asked by anoopsingh2, 1 year ago

please help me fast its urgent

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Answered by siddhartharao77
4
Given that Diameter of a roller = 84cm.

Then radius r = d/2

                        = 42cm.


Given length of a roller = 1m.
 
                                        = 100cm.


We know that Curved surface area of roller = 2pirh

                                                                          = 2 * 22/7 * 42 * 100

                                                                          = 2 * 22 * 6 * 100

                                                                          = 26400cm^2.

                                                                           = 2.64m^2



Therefore area of the road levelled in 1 revolutions = 2.64m^2.

Now, Area rolled in 750 revolutions = 2.64 * 750

                                                             = 1980m^2.



Hope this helps!
Answered by Anonymous
8
Hi,

Please see the attached file!

Thanks
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