Question

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Answer 1

Answer:

The answer is 2/5 . please mark me as brainlist

Answer 2

$\textsf{\large{\underline{Solution}:}}$

Let us assume that the original fraction is x/y.

When 1 is added to the numerator of the fraction:

$\rm: \longmapsto \dfrac{x + 1}{y} = \dfrac{1}{2}$

$\rm: \longmapsto y = 2x + 2$

$\rm: \longmapsto 2x - y = - 2 - (i)$

When 1 is added to the denominator of the fraction:

$\rm: \longmapsto \dfrac{x}{y + 1} = \dfrac{1}{3}$

$\rm: \longmapsto 3x = y + 1$

$\rm: \longmapsto 3x - y = 1 - (ii)$

Subtracting (ii) from (i), we get:

$\rm: \longmapsto - x = - 3$

$\rm: \longmapsto x =3$

Substituting the value of x in (ii), we get:

$\rm: \longmapsto 9 - y = 1$

$\rm: \longmapsto y = 8$

Therefore, the fraction is:

$\rm = \dfrac{x}{y}$

$\rm = \dfrac{3}{8}$

Which is our required answer.

$\textsf{\large{\underline{Verification}:}}$

When 1 is added to numerator, the fraction becomes:

$\rm = \dfrac{3 + 1}{8}$

$\rm = \dfrac{4}{8}$

$\rm = \dfrac{1}{2}$

When 1 is added to denominator, the fraction becomes:

$\rm = \dfrac{3}{8 + 1}$

$\rm = \dfrac{3}{9}$

$\rm = \dfrac{1}{3}$

Hence, our answer is correct (Verified)