Question

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Answer 1

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Answer 2

нєуα

нєяє ιѕ тнє αиѕωєя

gινєи єqυαтισи :-

f(χ) = χ² - ρ(χ - 1) - ¢

σи fυятнєя ѕσℓνιиg, ωє gєт

f(χ) = χ² - ρχ - ρ - ¢

нєяє, α = 1, в = -ρ αи∂ ¢ = -ρ - ¢

ѕυм σf zєяσєѕ =>

$\alpha + \beta = \frac{ - b}{a}$

=> -(-ρ)/1 = ρ

ρяσ∂υ¢т σf zєяσєѕ =>

$= > \alpha \beta = \frac{c}{a}$

=> (-ρ - ¢)/1 = -ρ - ¢

иσω,

я.н.ѕ. =

$(\alpha + 1)( \beta + 1) \\ \\ = > \alpha ( \beta + 1) + 1( \beta + 1) \\ \\ = > \alpha \beta + \alpha + \beta + 1$

ρυттιиg ναℓυєѕ ιи ιт.

ωє gєт

=> -ρ - ¢ + ρ + 1

=> 1 - ¢

= ℓ.н.ѕ.

нσρє тнιѕ нєℓρѕ.