Question

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Answer 1

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Answer 2

given that cosecA = 5/4

consider any right angle ∆ ABC.

we know that cosecA = hypotenuse/perpendicular

therefore the hypotenuse of the ∆ABC = 5 and perpendicular to = 4

sinA = perpendicular/base

cotA = base/perpendicular

cosA = base/hypotenuse

to find it's value, first we need to find the base.

by Pythagoras theorem,

➡ h² = b² + p²

➡ AC² = BC² + AB²

➡ 5² = BC² + 4²

➡ 25 = BC² + 16

➡ 25 - 16 = BC²

➡ 9 = BC²

➡ BC = √9

➡ BC = 3

hence, the base of the ∆ABC = 3

NOW, value of cotA = base/perpendicular

= 3/4

value of sinA = perpendicular/base

= 4/3

value of cosA = base/hypotenuse

= 3/5