Question

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Answer 1

Step-by-step explanation:

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Answer 2

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QUEATION

In series LR circuit XL = R and power factor of

the circuit is P1. When capacitor with capacitance

C such that XL = XC is put in series, the power

factor becomes P2. Calculate P1/P2.

ANSWER

P=VIcosϕ

and cosϕ=R2+XL2−XC2R

And, I=R2+XL2−XC2V

 ⟹P=R2+XL2−XC2V2R

P1=R2+R2V2R=2RV2

P2=R2+R2−R2V2R=R