Question

PLEASE HELP ME
find all pairs of natural numbers which can be the solution to the equation a+b=42

Answer 1

Answer:

a + b = 42

Using the concept of division into two groups,(Permutations and combinations)

Required number of solutions are: ⁴²⁺²⁻¹C₂₋₁ = ⁴³C₁

= 43

Hence,

42 such pairs can exist of (a,b) for which a+b = 42

Examples are: (0,42) , (42,0) , (1,41) , (41,1) .... etc.