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for 11) options b, d, e, angles can be possibly be those of a triangle
Step-by-step explanation:
a) we know that,
75°+ 54°+ 49° = 180° ( angle sum property of a ∆)
here by adding these values we get
178° ≠ 180°
so these are not an angles of a ∆
Repeat these steps for all:
in b) 96°+29°+55°=180°
=> 180°=180°
in c) 64°+32°+80° = 176°
176°≠180
in d) 29°+ 93° +58° =180°
180°=180°
in e) 35°+120°+25°=180°
180°=180°
10) given:
angles of a ∆ are in the ratio 4:5:6.
let 4x, 5x, 6x be the angles
then
4x + 5x + 6x =180°
=>15x = 180°
=> x = 180°
15
=> x = 12
so,
4x = 4 × 12 = 48°
5x = 5 × 12 = 60°
6x = 6 × 12 = 72°
To check whether these angles are right or wrong, you can use angle sum property of a triangle∆.
hope this helps you
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