Math, asked by rohanraj8487, 1 month ago

Please help me find out the answer I am request you to find out the answer if you don't know the answer don't answer it and do all questions please​

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Answered by kalyaniasokan20
0

Answer:

for 11) options b, d, e, angles can be possibly be those of a triangle

Step-by-step explanation:

a) we know that,

75°+ 54°+ 49° = 180° ( angle sum property of a ∆)

here by adding these values we get

178° ≠ 180°

so these are not an angles of a ∆

Repeat these steps for all:

in b) 96°+29°+55°=180°

=> 180°=180°

in c) 64°+32°+80° = 176°

176°≠180

in d) 29°+ 93° +58° =180°

180°=180°

in e) 35°+120°+25°=180°

180°=180°

10) given:

angles of a ∆ are in the ratio 4:5:6.

let 4x, 5x, 6x be the angles

then

4x + 5x + 6x =180°

=>15x = 180°

=> x = 180°

15

=> x = 12

so,

4x = 4 × 12 = 48°

5x = 5 × 12 = 60°

6x = 6 × 12 = 72°

To check whether these angles are right or wrong, you can use angle sum property of a triangle.

hope this helps you

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