Please help me find the answer
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2
Answer:
80 degrees
Step-by-step explanation:
consider the two triangles BAC and BOC
<A=<A (common)
<OBC =<ABO (given)
<OCB=<ACO (given)
therefore triangle BOC is similar to triangle BAC
thus <BOC=2*<BAC (angle subtended by an arc...)
Answered by
1
BOC is proved to be
90 + 1/2 of A (if for 1m)
BOC = 110
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