Math, asked by AnkithaBR, 1 year ago

please help me find this question

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jat8: it is too easy it belong to trignometry

Answers

Answered by Anonymous

Hope my answer helps you.

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AnkithaBR: I'm couldn't understand 3rd step denominator

Anonymous: I have taken LCM

AnkithaBR: please explain how u took LCM

Anonymous: the LCM between 1/root 2 and 1/ 2 root 2 is 2 root 2....so I multiplied the numerator of 1/ root 2 with 2

Anonymous: I guess u cant understand if I type like this!

AnkithaBR: okkk

AnkithaBR: 1root2 into 1root2 is 2 root 2

AnkithaBR: thank u

Answered by Anonymous

here given data is A=45 and B= 30

sinA= sin45= 1/√2

sinB=sin30=1/2
h
cosA=cos45=1/√2

(sinA)/( cosA+sinAsinB)=(1/√2)/(1/√2+1/√2×1/2)

here take LCM is 2√2

=2/2+1
=2/3

2/3 is your answer

AnkithaBR: and even cos45

AnkithaBR: It's OK u tried answer my question

AnkithaBR: Thank u

AnkithaBR: I can a little but i can understand it

AnkithaBR: can u talk Kannada

jat8: no

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